-0.01x^2+1.2x-5.8=22

Solution for -0.01x^2+1.2x-5.8=22 equation:

-0.01x^2+1.2x-5.8=22

We move all terms to the left:

-0.01x^2+1.2x-5.8-(22)=0

We add all the numbers together, and all the variables

-0.01x^2+1.2x-27.8=0

a = -0.01; b = 1.2; c = -27.8;
Δ = b2-4ac
Δ = 1.22-4·(-0.01)·(-27.8)
Δ = 0.328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{0.328}}{2*-0.01}=\frac{-1.2-\sqrt{0.328}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{0.328}}{2*-0.01}=\frac{-1.2+\sqrt{0.328}}{-0.02}
$